4sin^2x-4cosx+1=0

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Solution for 4sin^2x-4cosx+1=0 equation: 


Simplifying
4sin2x + -4cosx + 1 = 0

Reorder the terms:
1 + -4cosx + 4in2sx = 0

Solving
1 + -4cosx + 4in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -4cosx + -1 + 4in2sx = 0 + -1

Reorder the terms:
1 + -1 + -4cosx + 4in2sx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -4cosx + 4in2sx = 0 + -1
-4cosx + 4in2sx = 0 + -1

Combine like terms: 0 + -1 = -1
-4cosx + 4in2sx = -1

Add '-4in2sx' to each side of the equation.
-4cosx + 4in2sx + -4in2sx = -1 + -4in2sx

Combine like terms: 4in2sx + -4in2sx = 0
-4cosx + 0 = -1 + -4in2sx
-4cosx = -1 + -4in2sx

Divide each side by '-4osx'.
c = 0.25o-1s-1x-1 + in2o-1

Simplifying
c = 0.25o-1s-1x-1 + in2o-1

Reorder the terms:
c = in2o-1 + 0.25o-1s-1x-1

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